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Hi Nguyenkhiem, I am proud of your hard work and extra effort watching videos to learn. Well done!

Hi Diksha, I am so glad it was helpful. Thank you for commenting. I appreciate your compliment too, thank you. God bless you and sending love to you in India!

Hi Dinakhaled, Here is a great explanation from Google. Thank you for your question:) www.google.com/search?q=why+does+xenon+form+compounds+if+it+has+a+full+octet&rlz=1C1GCEA_enUS1005US1005&oq=why+does+xenon+form+compounds+if+it+has+a+full+octet&gs_lcrp=EgZjaHJvbWUyBggAEEUYOTIHCAEQIRigATIHCAIQIRirAjIHCAMQIRirAtIBCTE0OTgyajBqN6gCALACAA&sourceid=chrome&ie=UTF-8

The absorbance is read on the spectrophotometer. It comes from the wavelength of the light absorbed which the machine reads as transmittance, and then is calculated to absorbance. Maybe I misunderstood your question. You may want to ask your question to your professor so they can clarify. Thanks!

Hi Mosesdayanmorris:) You are welcome. I like your picture;)

Yes that is correct. Adding a solute keeps the solution in the liquid phase for a greater temperature range. Nice connection!

Hi Arevyah, praise the Lord! I am so glad. God bless you in your class. You've got this!

Hi Snook, that makes me so pleased it was helpful. I am proud of you for wanting to UNDERSTAND and not just memorize. Well done! :)

Hi Manuel, thank you for your kind comment. Good job working so hard!

Hi Amdiadiya, Wonderful! I am so glad to hear it. Thank you:)

I am so glad you think so. Thank you for your kind comment!

Hi e.m.ye.m.y, THANK YOU for your kind comment! I wish you were my student:) I am so pleased the videos have been helpful. God bless you in beautiful California.

I like it! Thank you:)

Hi Julie, I am so glad! I hope your class goes well:)

Hi Sunkaraswapna, sending love to you in India! Thank you for your comment:)

Hi Copernicofelinis, excellent question. Honestly, I do not know. At the general chemistry level we assume it is instantaneous and a non-issue. In real life, I do not have an answer. I suggest you ask your professor for their thoughts as well. Thank you for the great question!

@@OldSchoolChemistry considering how many years have passed since I last talked to my chem prof, it is safe to assume I would need a seance to ask him the question. And since he was a stubborn atheist, he would probably not answer even if he could. I would do the experiment myself, but nowadays it's easier to buy a semiautomatic rifle than a chemistry set... I think I would need three to five cells to give a strong enough (near short circuit) current to be read by a clamp ammeter on the middle salt bridge. And it would probably need to be a current probe attached to an oscilloscope because the transient could be just a few tens of microseconds... It would be epic seeing KCl breaking KCL, tho. Anyway, thanks for taking the time to reply, and kudos for your tutorials: they are a joy to watch. I love your enthusiasm.

@@copernicofelinis Thank you❤

Hi Angie, I am so glad it was helpful. Thank you for your comment!

Hi Hashemlafi, we do not include water because it is in the liquid phase. We only include aqueous and gas phases in the equilibrium expression. Thank you for your question!

​@@OldSchoolChemistry Thanks for your help ma'am 😊 I forgot that we don't include them in the equilibrium expression. Either way, my question didn't make any sense because the formula has to be balanced in the first place. So when I asked whether it should be divided by [H2O], that was just wrong because it has to be two molecules of H20 in the reactants.

Hi Sukanya, You are welcome! I hope your class goes well:)

I am so glad you think so - thank you!! :)

HI Nadiraslam, look at the actual (overall) chemical equation, and it can give you hints which is the slow step. That is really beyond the scope of a general chemistry class...tough!

Hi Daniyal! You are so welcome. I hope your class goes well:)

Hi Mohamed, I am so glad! Thank you for watching and for commenting:)

Hi Hiral, Great idea! Thank you for the recommendation:)

@@OldSchoolChemistry thanks for the reply mam, it made my day..truly means a lot..

I am so glad it was easy to understand! Way to go finding videos to help you "make it make sense." God bless you in your class!

Hi Aqilaisya, greetings to you in Malaysia! Thank you for your comment:) I am glad you thought it was very good.

HI AlokAK-ht7cu, That makes me so happy! Great job working so hard. God bless you on your Jee Exam:)

Hi geisalMINelf123, I am so glad it was helpful. Thank you for your comment:)

Hi Elijah, I am so glad you think so! This was a tough problem that asked everything possible in the hardest way! I am proud of your extra and hard work:)

@@PaperKoi. You are very welcome. God bless you in your studies and on your test!

@@L-zh2cs Oh good! AP likes this topic😉 Good job working hard.

@@OldSchoolChemistry thank you, you have no idea how much happier your words made me

@@MrEstradaG You’re very welcome! Thank you for your comment😊

@@vicentellosa7803 I’m so sorry! Visit your professor and they can help. God bless and help you in the class!

Hi Inayat, I will begin recording again in the fall. Thank you so much for your comment!

Hi OMBrsteej, thank you! I appreciate you watching and commenting:)

Hi The Bong Microbe, God bless you on your test! I am proud of your extra work:)

Hi IIT, I am not sure. I imagine it is an obvious and easy answer, but I do not know. Great question!!

Hi Nylonin, thank you for your question. AMU is different than mass. In essence 1 amu = 1 proton and 1 amu = 1 neutron. C-12 has 6 protons and 6 neutrons so its total amu is 12. I hope that helps. Thanks!

@@OldSchoolChemistry but isnt amu essentially used to calculate mass? what differs it from actual mass? thanks!

@@nylonin3817 Hi:) amu is the number of protons and neutrons...not their mass. If you take the mass of 1 proton and multiply it by Avogadro's number you get the mass of one mole of protons. So, the mass of 1 proton times Avogadro's number is 1 gram. I hope that helps. That is why we can use the same atomic mass on the periodic table as both the weighted average of an isotope (amu) and molar mass of that same element. It is the same number but amu and molar mass technically have different meanings. AMU = number of protons + neutrons. Molar mass is the mass of one mole of a substance. Thanks!

@@OldSchoolChemistry thank you!

Hi Michael, you are very welcome. I hope your class goes well:)

Hi Matthew, I appreciate that. I am glad it was helpful. Thank you very much for commenting!

Hi Lubega, I am so glad! Thank you for your response:)

Hi Meet Modh, that make me so happy! Thank you for letting me know. God bless you on your exam:)

Hi Sim, that is wonderful news and makes me so happy. Thank you for sharing! I hope your project goes well!!

Hi Inayat8503, I am so glad. Thank you for your comment. I hope your class goes well:)

Hi Milana, thank you☺. I appreciate your comment. I hope your class goes well!

Hi Hama, thank you for your comment:) You are so welcome!